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Calculation of Oscillation Period- Short Problem

  1. Nov 23, 2009 #1
    1. The problem statement, all variables and given/known data

    You drill a hole at the end of a solid thin rod of length 1.3 m, and then attach the rod through this hole onto an approximately frictionless pivot. You then release the rod from rest at a reasonably small angle from vertical, so that it executes simple harmonic motion.

    L=1.3m

    a.) What will be its oscillation period? _____ seconds

    b.) If the bottom of the rod varies its height above the ground by 2 cm during the oscillation, what was its initial angle from the vertical? ______ degrees
    (Note: You may assume the width of the stick is negligible to make this well defined.)


    2. Relevant equations

    T = 2pi * sq root (L/g)
    I = (1/3) M L^2 .... should I incorporate this equation for a thin rod?

    3. The attempt at a solution

    For part A, tried the T = 2pi * sq root (L/g) equation but got 2.2884 which was wrong
    I didn't do part b, b/c I think I am missing some key concept for this problem
     
  2. jcsd
  3. Nov 23, 2009 #2

    kuruman

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