- #1

BDM333

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## Homework Statement

You drill a hole at the end of a solid thin rod of length 1.3 m, and then attach the rod through this hole onto an approximately frictionless pivot. You then release the rod from rest at a reasonably small angle from vertical, so that it executes simple harmonic motion.

L=1.3m

a.) What will be its oscillation period? _____ seconds

b.) If the bottom of the rod varies its height above the ground by 2 cm during the oscillation, what was its initial angle from the vertical? ______ degrees

(Note: You may assume the width of the stick is negligible to make this well defined.)

## Homework Equations

T = 2pi * sq root (L/g)

I = (1/3) M L^2 ... should I incorporate this equation for a thin rod?

## The Attempt at a Solution

For part A, tried the T = 2pi * sq root (L/g) equation but got 2.2884 which was wrong

I didn't do part b, b/c I think I am missing some key concept for this problem