Calculation of Oscillation Period- Short Problem

[BDM333]

Homework Statement

You drill a hole at the end of a solid thin rod of length 1.3 m, and then attach the rod through this hole onto an approximately frictionless pivot. You then release the rod from rest at a reasonably small angle from vertical, so that it executes simple harmonic motion.

L=1.3m

a.) What will be its oscillation period? _____ seconds

b.) If the bottom of the rod varies its height above the ground by 2 cm during the oscillation, what was its initial angle from the vertical? ______ degrees
(Note: You may assume the width of the stick is negligible to make this well defined.)

Homework Equations

T = 2pi * sq root (L/g)
I = (1/3) M L^2 ... should I incorporate this equation for a thin rod?

The Attempt at a Solution

For part A, tried the T = 2pi * sq root (L/g) equation but got 2.2884 which was wrong
I didn't do part b, b/c I think I am missing some key concept for this problem

 

[kuruman]

Yes, you must consider the moment of inertia. This is a physical pendulum not a simple pendulum. Check out this site for more info

http://hyperphysics.phy-astr.gsu.edu/HBASE/pendp.html