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castrodisastro
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Homework Statement
A uniform rod of mass M, and length L swings as a pendulum with two horizontal springs of negligible mass and constants k1 and k2 at the bottom end as shown in the figure. Both springs are relaxed when the when the rod is vertical. What is the period T of small oscillations?
Homework Equations
T = 2π/ω
Iuniform rod = ⅓ml2 = ⅓ML2
ω = √[mgh / I] = √[Mg(½L) / ⅓ML2]
Potential Energy U = mgh = Mg(½L)
Kinetic Energy T = ½kx2 = ½(k1+k2)L2
The Attempt at a Solution
In order to find the period T, I need to find the angular velocity, ω.
To find the angular velocity I need to know the moment of Inertia for the uniform rod, and we need to know every component that would affect the motion of the rod when disturbed from equilibrium.
The moment of Inertia of the rod is given by ⅓ML2
and the restoring forces are Mg(½L) and ½(k1+k2)L2
Solving for T:
= 2π √[(⅓ML2) / (Mg(½L)+½(k1+k2)L2]
Factoring out an L from the numerator and denominator, and factoring out a ⅓ from the numerator, and a ½ from the denominator...
= 2π √[((⅓L)ML) / ((½L)(Mg+(k1+k2)L))]
The L's cancel and rearranging the ⅓ and the ½ I get...
= 2π √[(2ML)) / (3Mg+3(k1+k2)L)]
as my final answer.
The answer in the back of the book however, is
= 2π √[(2ML)) / (3Mg+6(k1+k2)L)]
and I have it on good authority that this book is NOT wrong.
Is my reasoning incorrect. Any help is appreciated.
Thank you