- #1
KevinFan
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Homework Statement
A very light, rigid rod with a length of 0.620m extends straight out from one end of a meter stick. The stick is suspended from a pivot at the far end of the rod and is set into oscillation.
(a)Determine the period of oscillation.
(b)By what percentage does this differ from a one meter long simple pendulum?
Homework Equations
omega=sqrt((mgh)/i)
omega=sqrt((g/l))
omega=(2Pi)/T
The Attempt at a Solution
I got the correct period for part a, and it's 2.19s
For the second part, I used omega=sqrt((g/l)), and omega is 3.13, and T is 2.007s.
I used (2.19-2.007)/2.19 to find the percentage which is 0.0835. However, it's wrong...
This seems like a simple question but I'm keep getting the second part wrong. Any suggestions?