Calculation of Peak Impact force

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SUMMARY

The discussion centers on calculating peak impact force using a theoretical equation due to budget constraints in a lab-scale drop weight impact testing machine project. The proposed equation is Impact Force = W √ 2h / δst, where W is the drop weight in Newtons, h is the drop height in meters, and δst is the deflection when the drop weight is statically applied in meters. Participants debated the feasibility of this approach compared to using load cells or accelerometers, emphasizing the need for assumptions regarding material behavior and collision characteristics.

PREREQUISITES
  • Understanding of impact force calculations
  • Familiarity with drop weight impact testing principles
  • Knowledge of material deformation and properties
  • Basic concepts of impulse-momentum and work-kinetic energy
NEXT STEPS
  • Research the use of accelerometers in impact testing setups
  • Study the assumptions behind impulse-momentum and work-kinetic energy methods
  • Explore linear material behavior and its implications in impact testing
  • Investigate alternative methods for measuring peak impact force without load cells
USEFUL FOR

Engineering students, researchers in material science, and professionals involved in impact testing and crashworthiness assessments will benefit from this discussion.

Karan Ratan
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I am a M-tech student working on a project of Drop weight impact testing machine for measuring the crashworthiness of structure. As it will be a lab-scale model, the budget doesn't allow me to include load cells for measuring peak impact force by load-displacement graph.
I am planning to calculate Average impact force as per the deformation obtained in specimen but
for getting the peak impact force(Elastic response) by theoretical approach, can i use the following equation

Impact Force = W √ 2h / δst
Where W = drop weight in N
h = drop height in m
δst = deflection when that drop weight is statically applied in m
Whether this theoretical calculation instead of load cell arrangement can yield me a comparable result of peak impact force ?
 
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Karan Ratan said:
I am a M-tech student working on a project of Drop weight impact testing machine for measuring the crashworthiness of structure. As it will be a lab-scale model, the budget doesn't allow me to include load cells for measuring peak impact force by load-displacement graph.
I am planning to calculate Average impact force as per the deformation obtained in specimen but
for getting the peak impact force(Elastic response) by theoretical approach, can i use the following equation

Impact Force = W √ 2h / δst
Where W = drop weight in N
h = drop height in m
δst = deflection when that drop weight is statically applied in m
Whether this theoretical calculation instead of load cell arrangement can yield me a comparable result of peak impact force ?

Welcome to the PF.

Are you saying that you cannot use simple accelerometers in this setup?
 
Impact

berkeman said:
Welcome to the PF.

Are you saying that you cannot use simple accelerometers in this setup?


I can use accelerometers but the data acquisition system required to get the readings can cost me. I am trying to keep my project as simple as possible so that it can be affordable for engineering college as an experimental setup of drop ωeight impact test to replace the charpy impact test ωhich can do the charpy impact test, crashωorthiness test and even penetration test.
 
I've seen approximations of peak impact force like you are describing, where one makes a couple of basic assumptions -- namely, impulse-momentum, assuming a perfectly elastic collision, along with work-kinetic energy, assuming a triangular pulse shape. Still too many unknowns. These unknowns are peak force, time duration, peak deformation.

I understand that you will be measuring the static deformation as well. So I assume that additional assumptions you've made include linear material behavior and material properties that are independent of rate effects. Is that more or less correct? Did any other assumptions go into your equation? Am I totally off base here and your equation is actually empirical?
 
I have encountered a vertically oriented hydraulic cylinder that is designed to actuate and slice heavy cabling into sections with a blade. The cylinder is quite small (around 1.5 inches in diameter) and has an equally small stroke. The cylinder is single acting (i.e. it is pressurized from the bottom, and vented to atmosphere with a spring return, roughly 200lbs of force on the spring). The system operates at roughly 2500 psi. Interestingly, the cylinder has a pin that passes through its...

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