Calculation of permissible error in physical quantity

In summary, the conversation is about calculating the permissible error for a physical quantity C. The rule for significant figures in multiplication or division is discussed and applied to find the value of C. However, there is a discrepancy in the calculation of (ΔA)/A.The conversation ends with a question about the rule for reporting significant figures in the permissible error ΔC.
  • #1
Abhishek Gupta
8
0

Homework Statement


I have doubt in calculating the permissible error. It goes as follows
Measure of two quantities along with the precision of respective measuring instrument is
A = 25.0 ± 0.5 m/s, B = 0.10 ± 0.01 s. A physical quantity C is calculated as C = A × B. What will be the value of C along with permissible error

Homework Equations


[itex]\frac { ΔC } {C} = \Big ( {\frac { ΔA } {A} + \frac {Δ B} {B} } \Big )
[/itex]

The Attempt at a Solution


STEP 1.
In the literature it is clearly mention that number of significant figures in result C is governed by the following rule.
"In multiplication or division, the final result should retain as many significant figures as are there in the original number with smallest number of significant figures."
Going by this rule C= 25.0 x 0.10 = 2.50 m = 2.5 m (rounding off to two significant figures).

STEP 2.
[itex]\frac { ΔC } {C} = \Big ( {\frac { ΔA } {A} + \frac {Δ B} {B} } \Big ) = \Big ( {\frac { 0.5 } {25.0} + \frac {Δ0.01} {0.10} } \Big ) =
0.2 + 0.1 = 0.3
[/itex]
ΔC = 0.3 × 2.5 =0.75 m
However, to what the significant figures after rounding off, the permissible error ΔC should be reported. Should ΔC=0.75m or 0.7m or something else What is the rule governing this?
 
Last edited:
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  • #2
Abhishek Gupta said:

Homework Statement


I have doubt in calculating the permissible error. It goes as follows
Measure of two quantities along with the precision of respective measuring instrument is
A = 25.0 ± 0.5 m/s, B = 0.10 ± 0.01 s. A physical quantity C is calculated as C = A × B. What will be the value of C along with permissible error

Homework Equations


[itex]\frac { ΔC } {C} = \Big ( {\frac { ΔA } {A} + \frac {Δ B} {B} } \Big )
[/itex]

The Attempt at a Solution


STEP 1.
In the literature it is clearly mention that number of significant figures in result C is governed by the following rule.
"In multiplication or division, the final result should retain as many significant figures as are there in the original number with smallest number of significant figures."
Going by this rule C= 25.0 x 0.10 = 2.50 m = 2.5 m (rounding off to two significant figures).

STEP 2.
[itex]\frac { ΔC } {C} = \Big ( {\frac { ΔA } {A} + \frac {Δ B} {B} } \Big ) = \Big ( {\frac { 0.5 } {25.0} + \frac {Δ0.01} {0.10} } \Big ) =
0.2 + 0.1 = 0.3
[/itex]
However, to what the significant figures after rounding off, the permissible error ΔC should be reported. Should ΔC=0.75m or 0.7m or something else What is the rule governing this?
Have you made an error in (ΔA)/A ?
 
  • #3
SammyS said:
Have you made an error in (ΔA)/A ?
Respected Sir
With all due respect I did n't get you
 
  • #4
Abhishek Gupta said:
Respected Sir
With all due respect I did n't get you
It was a very direct question.

Restated: What is 0.5/25 ?
 
  • #5
SammyS said:
It was a very direct question.

Restated: What is 0.5/25 ?

I apologize for the error . I have corrected it below.
STEP 2.

[itex]\frac { ΔC } {C} = \Big ( {\frac { ΔA } {A} + \frac {Δ B} {B} } \Big ) = \Big ( {\frac { 0.5 } {25.0} + \frac {Δ0.01} {0.10} } \Big ) =

0.02 + 0.1 = 0.12

[/itex]
ΔC = 0.12 × 2.5 =0.30 m
However, to what the significant figures after rounding off should the permissible error ΔC be reported. Should ΔC=0.30m or 0.3m or something else What is the rule governing this?
 

1. What is the significance of calculating permissible error in physical quantity?

The calculation of permissible error in physical quantity is important because it helps to determine the accuracy and reliability of experimental measurements. It also allows scientists to compare their results with established standards and to identify any sources of error in their measurements.

2. How is permissible error in physical quantity calculated?

The permissible error in physical quantity is calculated by taking into account the uncertainty of the measuring instrument and the precision of the measurement. This is typically done by using statistical methods, such as standard deviation, to determine the range of values within which the true value of the physical quantity is likely to fall.

3. What factors can affect the permissible error in physical quantity?

There are several factors that can affect the permissible error in physical quantity, including the quality and precision of the measuring instrument, environmental conditions, and human error. It is important to carefully consider and control these factors in order to obtain accurate and reliable measurements.

4. How does the permissible error in physical quantity impact scientific research?

The permissible error in physical quantity is crucial in scientific research as it allows scientists to determine the reliability of their results and make meaningful comparisons with other studies. It also helps to identify any potential sources of error and improve the accuracy of future measurements.

5. Can the permissible error in physical quantity be reduced?

Yes, the permissible error in physical quantity can be reduced by using more precise measuring instruments, controlling environmental factors, and repeating measurements to improve the accuracy. It is important for scientists to continuously strive for reducing the permissible error in order to obtain more accurate and reliable results.

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