Calculation of the velocity uncertainty

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To calculate the uncertainty in velocity v_1, defined as the cart length divided by time t_1, the constant cart length must be considered. The correct approach involves using the propagation of uncertainty formulas, specifically for division, which states that the relative uncertainty in the result is the square root of the sum of the squares of the relative uncertainties of the variables involved. The user is struggling with unit conversion and applying the formulas correctly, leading to confusion about obtaining the desired units of m/s. Clarification on the proper application of these formulas and unit consistency is needed to resolve the uncertainty calculation.
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Homework Statement


I need to calculate the uncertainty for the velocity v_1=(cart length)/t_1. The cart length is constant.


Homework Equations


That is what I am not sure about. I need to use the rule "dividing by a constant" to find the uncertainty. Is that

result q=B/x ,where B is the constant and

∆q=|1/B|* ∆x


The Attempt at a Solution


The problems is I get the units wrong when I apply this. i need m/s
My ∆t=0.0001s and the cartmass=0.129kg

∆v_1= |1/0.129m|* 0.0001s

This would give me s/m?

So I guess my fomrmula is wrong. Can someone help me finding the right approach to calculate the uncertainty?
Thanks.
 
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Basic Propagation of Errors of Precision

For z = x + y or z = x - y, then

\Delta z = \sqrt{\Delta x^2 + \Delta y^2}

For z = x*y or z = x/y then

\Delta z = z \sqrt{\left(\frac{\Delta x}{x}\right)^2 + \left(\frac{\Delta y}{y}\right)^2}

For z = xn,

\Delta z = n x^{n-1} \Delta x
 
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