What is the thickness of a steel bar with holes?

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SUMMARY

The discussion focuses on calculating the thickness of a steel bar with 10mm holes and a 2mm wall thickness. The overall thickness is determined to be 26mm when holes are aligned horizontally with 2mm steel between them. However, the actual thickness is less due to the arrangement of the holes, which may involve dimple features. The conversation also touches on the methods of hole formation, specifically drilling versus punching, and emphasizes the use of trigonometry to calculate distances between hole centers.

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  • Understanding of basic geometry and trigonometry
  • Familiarity with steel material properties
  • Knowledge of manufacturing processes such as drilling and punching
  • Ability to interpret technical drawings or images of mechanical components
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  • Research the properties of steel, focusing on wall thickness and structural integrity
  • Learn about the differences between drilling and punching in metal fabrication
  • Study trigonometric principles related to calculating distances and dimensions in mechanical design
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Mechanical engineers, manufacturing professionals, and students studying mechanical design or fabrication processes will benefit from this discussion.

GulfOnBoard
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TL;DR
Calculation of thickness.
I’m trying to calculate the thickness of a steel bar with holes. It’s hard to describe so here’s a picture Imgur: The magic of the Internet (the white circles are 10mm holes and the dark grey area are 2mm steel wallthickness).

If the holes would be horizontal inline to each other with 2mm steel between them and also 2mm steel at the outerwalls, the overall thickness would be 26mm, but with the pattern in the picture the thickness will be less, but exactly how much less?
 
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Why does the "bar" have dimple features? Are the holes formed by drilling or by punching? If by drilling, why would a "bar" be deformed?

1579912774155.png
 
Or is your question just one of how to calculate the distances using trigonometry? We can help with that if you haven't had trig yet. What is the application?
 
This doesn't need trigonometry. Draw a triangle between the centers of three adjacent circles. It is an equilateral triangle, you know its side lengths, and you can find its height with the usual formula (or Pythagoras if you want to derive that formula). Add the known distances to the left/right edges and you have the total width.
 
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