- #1
Henk Trekker
- 9
- 1
I started calculating the needed horsepower for my project copper granulator. i come out on 250hp, its very high, i think i made a fault with the formule.
Cross section area ( i take blades of the rotor height * withd ) = height : 10 cm, Withd: 12 cm.
10 * 12 = 120 / 2 = 60^2 cm
Yield stress of copper: 4830 psi ( shearstress 80 % of yieldstress ) = 3864 psi
Riadial cutter distance: 35.35cm
Rpm: 2000founded Formules:
3864 x 0.60 = 2318.4 lbs of force
Torque = Force * Radial cutter distance
2318.4 * 0.3535 = 819.5544 Meter-kg of torque
Answer * rpm =
8,195,544 * 2000 = 1639,108.8 / 12 = 136,592.4 / 550 = 248.35 hp
I know i make a lot of faults, but i want to learn it.
I will very happy if anyone can help me out.
Cross section area ( i take blades of the rotor height * withd ) = height : 10 cm, Withd: 12 cm.
10 * 12 = 120 / 2 = 60^2 cm
Yield stress of copper: 4830 psi ( shearstress 80 % of yieldstress ) = 3864 psi
Riadial cutter distance: 35.35cm
Rpm: 2000founded Formules:
3864 x 0.60 = 2318.4 lbs of force
Torque = Force * Radial cutter distance
2318.4 * 0.3535 = 819.5544 Meter-kg of torque
Answer * rpm =
8,195,544 * 2000 = 1639,108.8 / 12 = 136,592.4 / 550 = 248.35 hp
I know i make a lot of faults, but i want to learn it.
I will very happy if anyone can help me out.