- #1

kolleamm

- 477

- 44

The cylinder has an outer diameter of 5.6 cm , and an inner diameter of 5.0cm

Therefore its cross sectional area in that case should be

pi(2.8)^2 - pi(2.0)^2 = 12.06cm^2 let's just say 12cm^2

Its 60 cm long so its volume should be 12 * 60 = 720 cm^3

Also the density of the plastic material is 1.24g/cm^3 or 0.00124kg/cm^3

The motor has a torque of 40kg/cm

I know that Torque = Force * Radius, but in this case I'm a little unsure of how to calculate the force required since the object is not applying a force at just one point.

We can assume the object starts at the pivot and extends its 60cm size across the arm.

Any help is appreciated.

Thanks in advance