- #1
kolleamm
- 477
- 44
I'm trying to find out if my motor can rotate a robotic arm upwards from a resting position (we can assume the arm is a cylinder for simplicity).
The cylinder has an outer diameter of 5.6 cm , and an inner diameter of 5.0cm
Therefore its cross sectional area in that case should be
pi(2.8)^2 - pi(2.0)^2 = 12.06cm^2 let's just say 12cm^2
Its 60 cm long so its volume should be 12 * 60 = 720 cm^3
Also the density of the plastic material is 1.24g/cm^3 or 0.00124kg/cm^3
The motor has a torque of 40kg/cm
I know that Torque = Force * Radius, but in this case I'm a little unsure of how to calculate the force required since the object is not applying a force at just one point.
We can assume the object starts at the pivot and extends its 60cm size across the arm.
Any help is appreciated.
Thanks in advance
The cylinder has an outer diameter of 5.6 cm , and an inner diameter of 5.0cm
Therefore its cross sectional area in that case should be
pi(2.8)^2 - pi(2.0)^2 = 12.06cm^2 let's just say 12cm^2
Its 60 cm long so its volume should be 12 * 60 = 720 cm^3
Also the density of the plastic material is 1.24g/cm^3 or 0.00124kg/cm^3
The motor has a torque of 40kg/cm
I know that Torque = Force * Radius, but in this case I'm a little unsure of how to calculate the force required since the object is not applying a force at just one point.
We can assume the object starts at the pivot and extends its 60cm size across the arm.
Any help is appreciated.
Thanks in advance