What is the shortest path from A to B on the beach?

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The discussion focuses on determining the optimal drop-off point, C, along a 4 km beach for a sailor transporting passengers between two boats anchored at points A and B, located 3 km and 5 km off the beach, respectively. The solution involves minimizing the total distance AC + CB, leading to the conclusion that the optimal point C is 1.5 km down the beach from the point directly across from A. The method of reflections is employed to visualize the shortest path, demonstrating that the triangles formed are similar, which aids in solving the problem using geometric principles.

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calculus...no clue :(

Here is this question, I have no clue how to do it, I have tried it several different ways but cannot manage to get the right answer. Any help will be appreciated.

There is a 4 km long straight beach. At one end, there is a boat anchored at A, 3 km off the beach. At the other end, there is another boat anchored at B, 5 km off the beach. A sailor from the first boat is to bring a passenger to the beach and proceed to the second boat to pick up another passenger. At what point, C, along the beach should the first passenger be dropped in order to minimize the distance? Fill in the blank to answer this question. The boat whould land _______ km down the beach from a point across from A.


The answer is 1.50
 
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So you are looking for the C point on the beach that satisfies:
AC + CB is minimum. C is the common point of the 2 lines AC, and BC. Does that make you think of anything?
What AC equals to? HINT : Draw a line goes through A and is perpendicular to the beach. And let's see if you can get the answer.
Viet Dao,
 
So you end up with two triangles...do you use similar triangles ?

5/(4-x) = 3/x
you get the answer
x=3/2

if this is right how are the two triangles similar ?
 
punjabi_monster said:
So you end up with two triangles...do you use similar triangles ?

5/(4-x) = 3/x
you get the answer
x=3/2

if this is right how are the two triangles similar ?

You should not assume similar triangles. Actually, if you just draw the triangle ABC you are trying to minimize something about that triangle. What is it, and how do you find a minimum?
 
Method of "reflections"- imagine that the second boat, instead of being 5 km off shore is 5 km inland. In other words imagine that the shore line is a mirror and B' is "in the mirror", a reflection of B It is easy to see that the shortestest path from A to B' is the straight line from A to B'. But because "reflection" preserves distances, the point C where the straight line from A to B' crosses the beach also gives the shortest path from A to B that touches the beach at C. NOW you can use the geometry of the situation ("vertical angles") to show that the triangles are similar.
 

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