Calculus of Variation: "Help Me Understand a Step!

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SUMMARY

The discussion focuses on the application of integration by parts in the context of the calculus of variations, specifically regarding the integral expression for the action, S. The integral presented is \delta S(x,t)=-mc \int_a^b u_i d \delta x^i =0, where u_i represents the four-velocity. The participants clarify that the two functions involved in the integration by parts are u_i and \delta x^i, leading to the result \delta S(x,t)=-mc u_i \delta x^i |^b_a + mc\int_a^b \delta x^i \frac{du_i}{ds} ds.

PREREQUISITES
  • Understanding of calculus of variations
  • Familiarity with integration by parts
  • Knowledge of four-velocity in physics
  • Basic proficiency in differential calculus
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  • Study the principles of calculus of variations in depth
  • Learn the application of integration by parts in functional analysis
  • Explore the concept of four-velocity in the context of relativistic physics
  • Investigate the derivation of action principles in classical mechanics
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Students and researchers in physics, particularly those studying classical mechanics and the calculus of variations, will benefit from this discussion.

Gavroy
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hey

I do not understand a step here!

The integral is:

\delta S(x,t)=-mc \int_a^b u_i d \delta x^i =0

and now they say one should do integration by parts, but I do not know how this should work here?

Where are my two functions?As far as I see there is only the four-velocity and I do not how it depends on the differential so I wanted to ask you whether one of you could explain this step to me.

The result should be:

\delta S(x,t)=-mc u_i \delta x^i |^b_a + mc\int_a^b \delta x^i \frac{du_i}{ds} ds

I have not a clue what happened there! Can you help me?
 
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It's probably clearer if you write the original integral in longhand:

<br /> \int_a^b u_i \frac{d (\delta x^i)}{ds} ds <br />

The two functions are u_i and \delta x^i.
 

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