MHB Calc Solved! Get Quick Help With Your Calculus Q

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SUMMARY

The discussion focuses on solving a calculus problem involving the chain rule and partial derivatives. The function f(x) is defined as arctan(x), with its derivative calculated as df/dx = 1/(x^2 + 1). The variable x is expressed as a function of u and v, specifically x = e^u + ln(v), leading to the partial derivatives ∂x/∂u = e^u and ∂x/∂v = 1/v. This establishes a clear method for applying the chain rule in multivariable calculus.

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  • Understanding of the chain rule in calculus
  • Knowledge of partial derivatives
  • Familiarity with the arctangent function
  • Basic concepts of multivariable functions
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  • Study the application of the chain rule in multivariable calculus
  • Learn about partial derivatives and their significance
  • Explore the properties and applications of the arctangent function
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Students enrolled in calculus courses, educators teaching calculus concepts, and anyone looking to deepen their understanding of multivariable calculus and the chain rule.

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please I need solve of this question very quickly
 

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Then you had better get started! Can we at least assume you are taking a Calculus class?

Do you know the "chain rule"?

f is a function of x and x itself is a function of u and v so
$\frac{\partial f}{\partial u}= \frac{df}{dx}\frac{\partial x}{\partial u}$ and $\frac{\partial f}{\partial v}= \frac{df}{dx}\frac{\partial x}{\partial v}$.

f(x)= arctan(x) so $\frac{df}{dx}= \frac{1}{x^2+ 1}$

$x= e^u+ ln(v)$ so $\frac{\partial x}{\partial u}= e^u$ and $\frac{\partial x}{\partial v}= \frac{1}{v}$.
 
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