Calories Required to Raise the Temp of Aluminum

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    Aluminum Calories
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Homework Help Overview

The discussion revolves around calculating the calories required to raise the temperature of aluminum, specifically 26 grams from 20°C to 115°C, using the specific heat capacity of aluminum.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the specific heat formula to find the heat required, but questions the validity of their answer in relation to the options provided in their workbook.

Discussion Status

Participants have acknowledged the calculations presented by the original poster, with some suggesting that there may be a typo in the workbook. There is no explicit consensus on the correctness of the workbook's options.

Contextual Notes

The original poster expresses uncertainty about the accuracy of their workbook's answer choices, indicating a potential discrepancy between their calculated result and the provided options.

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Homework Statement



How many calories are required to raise the temperature of 26 grams of aluminum from 20°C to 115°C?

Homework Equations



Specific heat of aluminum is 0.22 cal / g x °C

Amount of heat = SH x mass x (T2-T1)

The Attempt at a Solution



Plugging numbers into the 2nd equation gives me:

cal = 0.22 x 26 x 95
cal = 543.4

So I get 543.4 calories as the answer, or 5.4 x 102 calories. However, my workbook only has the following as possible answers:

5.4 x 10+1
5.4 x 10-1
5.4 x 10+3
5.4 x 10-3

Have I missed something here, or is my workbook wrong?
 
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I'm no expert in this, but your numbers look okay to me.
 
I agree with your answer, Drakkith. It seems to me that your workbook has a typo, unless you copied some of the information incorrectly.
 
Mark44 said:
I agree with your answer, Drakkith. It seems to me that your workbook has a typo, unless you copied some of the information incorrectly.

Nope, that's exactly what it says.
Thanks guys.
 

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