Physics heat problem Using calories.

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Homework Help Overview

The problem involves calculating the calories required to raise the temperature of a 44 g gold chain from 20°C to 125°C, focusing on the specific heat capacity of gold.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to incorporate the heat capacity of gold in the calculation, questioning the initial approach of multiplying mass and temperature change alone.

Discussion Status

Some participants have provided guidance on the importance of using the specific heat capacity of gold, while others have noted the differences in thermal properties among various materials. There is an acknowledgment of the need to convert energy units if using specific heat data from external sources.

Contextual Notes

Participants reference the variability in thermal properties of different materials, indicating that assumptions about uniformity in heating requirements may not hold. There is mention of a need to convert units from Joules to Calories when using specific heat values from external references.

astru025
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Homework Statement



How many calories will it take to raise the temperature of a 44 g gold chain from 20°C to 125°C?


Homework Equations



You are trying to raise the temperature of 44 g. of gold by 105 degrees celsius. I tried 44 x 105 but this answer was incorrect.

3. The Attempt at a Solution
The answer is got was 4620 cal. But this was not correct.
 
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You also have to multiply by the heat capacity of gold(solid) to get the number of calories.

Chet
 
They told you it was gold because different materials have different thermal properties. It takes more energy to heat up 44g of water by 105C then it does to do the same if it's gold, wood, air...

See the table of data for various materials down here..
http://en.wikipedia.org/wiki/Heat_capacity#Table_of_specific_heat_capacities

Note the units. If you use this data you will have to convert the resulting energy from Joules to Calories.
 
Thank you very much! I came up with the correct answer
 

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