1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calorimetry A thirsty nurse cools a 2.40 L

  1. Jul 22, 2012 #1
    1. The problem statement, all variables and given/known data

    A thirsty nurse cools a 2.40 L bottle of a soft drink (mostly water) by pouring it into a large aluminum mug of mass 0.250 kg and adding 0.123 kg of ice initially at -15.5 degree celsius . If the soft drink and mug are initially at 20.2 degree celsius, what is the final temperature of the system, assuming no heat losses?

    2. Relevant equations

    Q1+Q2+Q3+Q4+Q5=0
    Q=Mc(change in T)
    Q=ML
    C ice= 2010 (given)
    C water = 4190 (given)
    C Al= 904
    L = 3.34*10^5 (given)
    M drink = Density *Volume = (1000)(.0024)=2.4

    3. The attempt at a solution

    Q1=M ice (C ice) (Temp) = .123(2010)(0--15.5) = 3832
    Q2=M ice (L) = .123 (3.34*10^5) = 41082
    Q3=M ice (C water) (Temp) = .123 (4190)(T-0) = 515.4 (T)
    Q4=M drink (C water) (Temp) = 2.4 (4190) (T-20.2) = 10056 (T-20.2)
    Q5=M Al (C Al) (Temp) = .25(904)(T-20.2) = 226 (T-20.2)

    (3832)+(41082)+515.4 (T) + 10056 (T-20.2) + 226 (T-20.2) = 0

    I keep getting the wrong answer. I think I am missing a Q or misinterpreting one of them
     
  2. jcsd
  3. Jul 22, 2012 #2
    Re: Calorimetry

    never mind I was right 15.1 is the final temp
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Calorimetry A thirsty nurse cools a 2.40 L
  1. Calorimetry homework (Replies: 0)

  2. Calorimetry problem (Replies: 4)

Loading...