- #1

mizzy

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## Homework Statement

What mass of ice at -10.0 degrees celsius is needed to cool a whale's water tank, holding 1.20 x 10^3 m^3 of water, from 20.0 degrees down to a more comfortable 10 degrees.

## Homework Equations

Q = mc *delta T

Q = mL

## The Attempt at a Solution

i'm trying to fill out a table with knowns and unknowns before I actually solve the problem. This is what i got, can someone help me with the temperatures?

ICE: mass = x

c = 2090 J/kg C

Ti = -10.0

Tf = 0

MELT: mass = x

L = 3.33 x 10^5

ICE - WATER: mass = x

c = 4190

**This is where I'm stuck what's the temperature?**

Ti = ?

Tf = ?

WATER: mass = ??

c= 4190

Ti = 20.0

Tf = 10

Can someone let me know where i went wrong?? I still need to find the mass of water.

Thanks!