Calucating the solubility product of Silver Chloride

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Discussion Overview

The discussion revolves around calculating the solubility product (Ksp) of silver chloride (AgCl) based on a scenario involving the treatment of AgCl with sodium carbonate (Na2CO3). Participants explore the implications of the remaining chloride ion concentration after the reaction and the relevant equations for Ksp.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • One participant presents a homework problem involving the treatment of AgCl with Na2CO3 and asks for help in calculating Ksp.
  • Another participant questions the concentration change of Cl- due to the excess carbonate, suggesting that this could affect calculations.
  • A participant mentions calculating the concentration of Cl- by converting grams per liter to molarity but expresses uncertainty about the next steps.
  • There is a suggestion to describe the chemical processes occurring in the solution when carbonate is added, indicating a need for conceptual clarification.
  • A participant attempts to calculate Ksp using derived concentrations but questions the relevance of the Na2CO3 concentration and volume in their calculations.

Areas of Agreement / Disagreement

The discussion reflects uncertainty and lack of consensus on the calculations and the role of Na2CO3 in the reaction. Participants express differing levels of understanding and approaches to the problem.

Contextual Notes

Participants have not fully resolved the implications of the carbonate addition on the chloride concentration or the overall calculation of Ksp. There are unresolved assumptions regarding the impact of excess carbonate on the system.

aati2sh
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Homework Statement


A sample of AgCl was treated with 5ml of 2M Na2CO3 solution to produce Ag2CO3. The remaining solution contained 0.003 g of Cl- per litre. Calculate the solubility product of AgCl.(Ksp of Ag2CO3 = 8.2 ×10-12)

Homework Equations


ksp of AgCl = [Ag+]×[Cl-]
ksp of Ag2CO3 = [2Ag+]2×[CO3--]

The Attempt at a Solution



I couldn't think of any idea. So, entered this forum. Please help.
 
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Can you calculate concentration of Cl-?

There was a huge excess of carbonate. Did it concentration change much?
 
Yes. I calculated the concentration by dividing gm/litre by 35.5 to give molarity. But, I don't know where to go beyond.
 
I asked you a question, have you tried to answer it?
 
I don't know how to start.
 
Try to describe what is happening in the solution when the carbonate is added.
 
I tried this:
Ksp of Ag2CO3 = [2xSolub.]2x[Solub.]
=> Solubility = 1.270334x10-4 = [Ag+]
Now,
[Cl-]=0.003/35.5 M = 8.45 x 10-5
Ksp of AgCl = 1.270334x10-4 x 8.45 x 10-5 = 1.073 X 10-8.

Why was concentration and volume of Na2CO3 was given if this is correct?
 

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