Calulate chance to get x heads in y flips

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Homework Help Overview

The discussion revolves around calculating the probability of obtaining a specific number of heads (x) in a given number of coin flips (y), where x is less than or equal to y. The subject area pertains to probability theory and combinatorics.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for calculating the probability, specifically referencing the binomial coefficient and the total number of outcomes for y flips. There is also a question regarding the specific case of getting 10 heads in 5 flips, which raises concerns about the validity of the scenario.

Discussion Status

The conversation includes attempts to clarify the formula and its application to specific examples. Some participants express uncertainty about the feasibility of certain outcomes, indicating a lack of consensus on the interpretation of the problem.

Contextual Notes

There is an implicit assumption that the coin is fair, and the discussion does not address any constraints or rules imposed by the homework assignment.

zeion
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Homework Statement



So if I wanted to get the chance to get x heads in y flips (x <= y)
I use y choose x / 2^y right?

Homework Equations





The Attempt at a Solution

 
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For a fair coin, yes.
 
So the chance of getting 10 heads with 5 flips is 0.3125? ;-)
 
skeptic2 said:
So the chance of getting 10 heads with 5 flips is 0.3125? ;-)
See below.
zeion said:
So if I wanted to get the chance to get x heads in y flips (x <= y)[/color]
I use y choose x / 2^y right?
 
I win.
 

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