Can a Non-Self-Adjoint Element Have a Real Spectrum?

  • Context: Graduate 
  • Thread starter Thread starter jostpuur
  • Start date Start date
  • Tags Tags
    Spectrum
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 3K views
jostpuur
Messages
2,112
Reaction score
19
Let [tex]X[/tex] be a [tex]C^*[/tex]-algebra. I know that if [tex]x\in X[/tex] is self-adjoint, then its spectrum is real, [tex]\sigma(x)\subset\mathbb{R}[/tex]. I haven't seen a claim about the converse, but it seems difficult to come up with a counter example for it. My question is, that is it possible, that some [tex]x\in X[/tex] has a real spectrum, but still [tex]x^*\neq x[/tex]?
 
Physics news on Phys.org
jostpuur said:
My question is, that is it possible, that some [tex]x\in X[/tex] has a real spectrum, but still [tex]x^*\neq x[/tex]?
Yes it is. Take for instance the 2x2 matrix (so [itex]X=M_2(\mathbb{C})[/itex])

[tex]x = \begin{pmatrix}a & 1 \\ 0 & b\end{pmatrix},[/tex]

where a and b are any real numbers. The spectrum of x is {a,b} but x is not selfadjoint.
 
I see.

(hmhmhmh... I didn't receive mail notification of your response...)
 
I am facing the same problem (see https://www.physicsforums.com/showthread.php?t=257751)

On the internet I found a reference, however I don't have acces to it:
http://oai.dtic.mil/oai/oai?verb=getRecord&metadataPrefix=html&identifier=AD0736116"

In general you can not say anything about the eigenvalues of a real (unsymmetric) matrix. However, if you can write your matrix as a product of matrices then analyzing them you may say something about the eigenvalues of the big matrix.

I put here two articles, maybe you will find them usefull.
 

Attachments

Last edited by a moderator:
HallsofIvy said:
You will only get e-mail notification if you "subscribe" to a thread. To do that, clilck on "Thread Tools" at the top of the thread, then click on "Subscribe to this Thread".

But isn't the subscribing automatic, so that one has to unsubscribe a thread if one doesn't want notifications. I didn't do anything with thread tools, and I got the notification of your post now.

There is a non-zero probability for the possibility, that I casually destroyed the first notification without later remembering it. I cannot know it for sure, of course... I was merely mentioning the remark anyway.
 
When you initially join this forum you are offered the option of automatic "subscription" or not. I chose not because I don't want an e-mail everytime someone responds to one of the threads I responded to. I can't delete all those e-mails AND respond to questions!