Can a Spider's Acceleration on a Spider Web Be Supported by its Tension?

[terryW16]

Homework Statement

A 2.0 X 10^-4 kg spider is suspended from a thin strand of spider web. The greatest tension the strand can withstand is 2.0 X 10^-3 N. if the spider was to ascend the strand from rest going to 1.0 m/s in 4.0 s with a steady acceleration, will the strand be able to support the motion?

Homework Equations

The Attempt at a Solution

2.0 X 10^-4 kg (9.8 m/s²) = 1.96 X 10^-3 kg(m)/s²

2.0 X 10^-4 kg (0.25 m/s²) = 5.0 X 10^-5

1.96 X 10^-3 + 5.0 X 10^-5 = 2.46 X 10^-4
yes because 2.0 X 10^-3 is greater than 2.46 X 10^-4

 

[Delphi51]

1.96 X 10^-3 + 5.0 X 10^-5 = 2.46 X 10^-4

Something has gone wrong here. Better run it through again.
It looks like your approach is correct, though difficult to follow.
Maybe better to write
F = ma
T - mg = ma
T = ma + mg = m(a+g), then put in the numbers.
This way, there is only one calc, half the chance of killing it with a typo!