Can a Waterfall Ever Become Supersonic?

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SUMMARY

The discussion centers on calculating the minimum height required for a waterfall to achieve supersonic speeds, specifically exceeding 340 m/s, the speed of sound. The key equations utilized include the kinematic equation S = ut + 1/2 at² and the velocity relationship v = v₀ + gt. The solution involves solving a quadratic equation derived from these relationships, emphasizing the need to express time in terms of height to find the necessary height for supersonic flow.

PREREQUISITES
  • Understanding of kinematic equations, specifically S = ut + 1/2 at²
  • Knowledge of gravitational acceleration (g = 9.8 m/s²)
  • Familiarity with the concept of supersonic speed and the speed of sound (340 m/s)
  • Basic algebra skills for solving quadratic equations
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics
  • Learn about the principles of fluid dynamics and how they relate to waterfall mechanics
  • Explore the effects of air resistance on falling objects and its impact on speed calculations
  • Investigate real-world examples of waterfalls and their flow rates to understand practical applications
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Students in physics or engineering, educators teaching kinematics, and anyone interested in fluid dynamics and the physics of motion.

spacethisride
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Homework Statement


According to geologists, the water in a waterfall was supersonic, that is, it fell with speeds in excess of the speed of sound. Ignoring air resistance, what is the minimum height necessary to create a supersonic waterfall? (The speed of sound may be taken to be 340 m/s.)

Homework Equations


Treating water as particles, water falling down the fall is acted upon by gravity. Using the Newton's equation...I think??

S = ut + 1/2 at^2

The Attempt at a Solution



S = ut + 1/2 at^2

h = 340t + (9.8/2)t^2
4.9t^2 +340t - h = 0. Solve the quadratic equation for t?

But I have two variables...(h and t) so I don't know how to go any further...
 
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you need to use the veloctiy relationship

[tex]v = v_0 + gt[/tex]

to find the time required to reach 340 m/s then use that time in the distance relationship to find the distance.
 

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