Can Adding Ice and Steam Change Water Temperature?

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SUMMARY

This discussion focuses on thermal equilibrium calculations involving water, ice, and steam. Judy's scenario requires determining the mass of ice needed to achieve a final temperature of 75.0°C when mixed with boiling water. The second question involves calculating the original mass of steam at 100°C after placing a 0.03 kg ice cube at 0°C in an insulated box, resulting in a final temperature of 23°C. The third question addresses the final temperature when 1 kg of water at 20°C is heated by the condensation of 30 g of steam at 100°C. Key equations discussed include heat transfer principles and specific heat calculations.

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Students studying thermodynamics, physics enthusiasts, and anyone involved in heat transfer calculations will benefit from this discussion.

jayphysics
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1.) Judy places .150 kg of boiling water in a thermos bottle. How many kilograms of ice at -12.0 C must Judy add to the thermos so that the equilbrium temperature of the water is 75.0 C?

2.) A 0.03 kg ice cube at 0C is placed in an insulated box that contains a fixed quantity of steam at 100 C. When thermal equilibrium of this closed system is established, its temperature is found to be 23C. Determine the original mass of the steam at 100 C.

3.) What will the final temperature if 1 kg of water at 20C is heated by the condensation of 30 g steam at 100 C?
 
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Hi jayphysics,

Forum rules state you must show some work in order to get homework help. What have you tried so far? What equations/concepts do you think you might use? What are you stuck on?
 
Well, for the 2nd question, I think we can use the equation: (Mice)(Lf) + (Mw)(Cw)(Change in Temp) = (Ms)(Lv) + (Msw)(Cw)(Change in Temp) since heat lost will be equal to heat gained. But I am not sure. Is this right?

For the 3rd question, can we use the equation: (Mass of water)(Specific heat capacity of water)(Temp of water) = (mass of steam)(Latent heat of vaporization)

Can anyone help
 

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