Can an Airplane Fly Fast Enough to Stay in Constant Sunlight?

  • Thread starter Thread starter teddef21
  • Start date Start date
  • Tags Tags
    Airplane Equator
Click For Summary
SUMMARY

An airplane must fly at a speed equal to the Earth's rotational speed to remain in constant sunlight or darkness. At the equator, this speed is approximately 1670 kilometers per hour (km/h), corresponding to the Earth's circumference divided by the time it takes for one complete rotation. For 40 degrees North Latitude, the required speed is lower due to the reduced circumference at that latitude, which can be calculated using basic trigonometric principles. The discussion emphasizes the importance of understanding Earth's geometry and rotation for solving this problem.

PREREQUISITES
  • Understanding of Earth's circumference and rotation speed
  • Basic trigonometry for calculating diameters at different latitudes
  • Familiarity with the concept of local solar time
  • Knowledge of physics principles related to motion and speed
NEXT STEPS
  • Calculate the Earth's circumference using the formula C = 2πr
  • Learn about the relationship between latitude and the Earth's diameter
  • Explore the concept of local solar time and its implications for flight
  • Study the physics of motion to understand speed and distance relationships
USEFUL FOR

Students of physics, aviation enthusiasts, and anyone interested in the relationship between Earth's rotation and flight dynamics.

teddef21
Messages
1
Reaction score
0
1. A)How fast and in what direction would an airplane need to fly(relatively close to the ground) around the equator to always stay in sunlight or darkness?
B) How fast and in what direction would an airplane need to fly at 40 degrees North Latitude to always stay in sunlight or darkness?
Im having trouble figuring out what equation would be best to use for this problem. I am new in physics and am pretty mathmetically challenged so any help would be greatly appreciatied
 
Physics news on Phys.org
The simplest case is assume it flys around the equator at the same speed the Earth rotates, so it always has the same local (sun) time.
Then you just need the cicumference of the Earth (hint definition of the metre) and the time taken for the Earth to rotate (for extra credit - this isn't 24hours).

For 40deg lat just work out what the diamter of Earth is at that latitude, it only involves drawing a triangle.

To make it more complicated, you could assume it takes off at dawn and lands in the same place just before dusk, it would still have been in sunlight but doesn't need to have flown as fast. This might be overcomplicating the question for a beginner class.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
5
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 3 ·
Replies
3
Views
10K