Can an electron in an s-orbital exist at the nucleus (r=0)?

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    Electron Nucleus
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SUMMARY

The probability of finding an electron in a 1s orbital at the nucleus (r=0) is definitively zero, as established by the formula Prob = (4/a^3)*(r^2)*exp(-2r/a), where the r^2 term indicates that the volume element at r=0 is zero. This conclusion contradicts some common teachings in chemistry, which may suggest otherwise. The nucleus, being larger than a point, has a non-zero volume element, allowing for a non-zero probability of finding particles within it, but not for the electron at r=0.

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Steven Hanna
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My quantum textbook says that the probability of finding an electron in a 1s orbital between r and r+dr is given by Prob = (4/a^3)*(r^2)*exp(-2r/a) dr. In this case, Prob(0) = 0 because of the r^2, which is part of the volume element in spherical polar. Does this mean that it is impossible to find an electron at r = 0? I have learned the opposite in several chemistry classes, so I would very much appreciate if someone could clear this up.
Thanks!
 
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The volume element at r = exactly zero is 0. The nucleus is somewhat bigger than that, and its volume element is non-zero, and therefore so is the probability.
 
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Vanadium 50 said:
The volume element at r = exactly zero is 0. The nucleus is somewhat bigger than that, and its volume element is non-zero, and therefore so is the probability.
Ah of course. Thank you!
 

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