Can Analytical Continuation Extend Asymptotic Expansions to Lower Values of x?

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Discussion Overview

The discussion revolves around the potential of analytical continuation to extend asymptotic expansions of integrals to lower values of x. Participants explore the implications of such extensions for evaluating integrals of the form \(\int_{x}^{\infty}F(t)dt\) as x approaches both large and small values.

Discussion Character

  • Exploratory, Debate/contested, Conceptual clarification

Main Points Raised

  • One participant proposes that the asymptotic development of the integral \(\int_{x}^{\infty}F(t)=g(x)[1+a/x+b/x^{2}+c/x^{3}+...]\) could be useful for calculating the integral at lower values of x, such as x=1, 2, 3.
  • Another participant questions the necessity of computing the integral as x approaches infinity, suggesting that if the integral exists for all x, the limit must be zero without further computation.
  • A different viewpoint emphasizes the interest in evaluating the integral for large values of x, such as x=100 or x=1,000,000, in addition to lower values.
  • One participant clarifies that evaluating the limit as x approaches infinity is fundamentally different from the goal of calculating specific integral values at lower x.

Areas of Agreement / Disagreement

Participants express differing views on the relevance and implications of extending asymptotic expansions to lower values of x, indicating that the discussion remains unresolved with multiple competing perspectives.

Contextual Notes

There are assumptions regarding the behavior of the integral and the conditions under which analytical continuation might be applicable, which are not fully explored or agreed upon.

eljose
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Let,s suppose we have the asymptotyc development of the integral:

[tex]\int_{x}^{\infty}F(t)=g(x)[1+a/x+b/x^{2}+c/x^{3}+...][/tex]

where a,b,c,.. are known constants and g(x) is a known function then you all will agree that this expression could be useful to compute the integral when x-------->oo, my question is if this expression can be analytically continued to calculate the integral for low x for example x=1,2,3...
 
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Why would I want to compute the integral

[tex]\int_{x}^{\infty}F(t)dt[/tex]

as x tends to infinity? If that integral exists for all x, then obviously I know that the limit, as x tends to infinity must be zero without doing any computation.
 
yes but perhaps you are interested in knowing the values of the integral for big x x=100,1000,100000000000000 or for low x x=1,2,3,4,...
 
but that is strictly different from evaluating a limit as x--->infinty.
 

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