DuckAmuck
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For example, does this always hold true?
M_ab = v_a × w_b
If not, where does it break down?
M_ab = v_a × w_b
If not, where does it break down?
The discussion centers on the expression of matrices as the product of two vectors, specifically through the outer product. It is established that not all matrices can be represented in this form, particularly those with rank greater than one, as they cannot be expressed as a single outer product of two vectors. The conversation highlights that any matrix of rank n can be represented as a sum of n rank-1 matrices, which is related to the concept of singular value decomposition. Additionally, the determinant of such rank-1 matrices is always zero due to their column dependencies.
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hilbert2 said:Let's say there are a column vector ##A = \begin{bmatrix}a \\ b\end{bmatrix}## and row vector ##B = \begin{bmatrix}c & d\end{bmatrix}## that have
##AB = \begin{bmatrix}ac & ad \\ bc & bd\end{bmatrix} = \begin{bmatrix}0 & 1 \\ 1 & 0\end{bmatrix}##.
Is this possible, knowing that ##xy = 0## for real numbers ##x,y## implies that either ##x=0## or ##y=0## ?
It can always be done by a linear combination of those where ##\operatorname{rank}M## is the minimal length of it.DuckAmuck said:For example, does this always hold true?
M_ab = v_a × w_b
If not, where does it break down?
DuckAmuck said:For example, does this always hold true?
M_ab = v_a × w_b
If not, where does it break down?
Sure, they are rank one matrices.hilbert2 said:Also, I guess the determinant of this kind of matrices (if they're square) is always zero, as the columns are multiples of each other. This is a very limiting property for a matrix.
fresh_42 said:The question gets interesting, if we ask for the minimal length of linear combinations of ##x\otimes y \otimes z## to represent a given bilinear mapping, e.g. matrix multiplication. If we define the matrix exponent ## \omega := \min\{\,\gamma\,|\,(A;B) \longmapsto A\cdot B = \sum_{i}^Rx_i(A) \otimes y_i(B) \otimes Z_i \,\wedge \, R=O(n^\gamma)\,\} ## then ##2\leq \omega \leq 2.3727## and we do not know how close we can come to the lower bound.