Can any two electrodes from the table make voltaic cell?

In summary, CroSinus says that, if you randomly choose two half reactions from the table attached to this post, the upper couple that you choose will act as the anode and the lower couple will act as the cathode of the battery.
  • #1
CroSinus
32
1
Hello everybody,

I would like to ask you a question about voltaic cells. Can any two electrodes from the table attached to this post make a voltaic cell? There will always be a potential difference no matter which half reactions you select. From my point of you, any two electrodes (or half reactions) can make a voltaic cell. What do you say?

Thanks for help,
CroSinus
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  • #2
In principle - yes.

Many combinations are not practical though.
 
  • #3
Thanks for answering my post.
CS

But one thing is not clear to me. If we take into consideration formula:

delta G = - z*F*E
the spontaneous half reactions imply negative ΔG. In other words only chemical half reactions for which ΔG is negative are spontaneous. But not all half reactions from the table given above are spontaneous.

How can two non spontaneous chemical reactions make a voltaic cell?
 
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  • #4
You are mistaking half reactions and reactions.
 
  • #5
I don't know. In my opinion, if I reconsider the problem once again, a voltaic cell will function only if two spontaneous half reactions take place at the electrodes. One of the half reactions must be spontaneous oxidation, and another spontaneous reduction.

Am I right? I would appreciate your comments about the problem. CS
 
  • #6
No, half reactions are not spontaneous. Whole reaction (which combines two half reactions) can be.
 
  • #7
You are right. Like in the Daniell cell. The oxidation of zinc electrode is spontaneous while the oxidation of copper electrode is not. The reduction of Cu2+ ions is spontaneous instead.

But what if I take Li/Li+ and K/K+ electrodes. Would such a cell be possible?
 
  • #8
Possible? Definitely. Good luck designing it :wink:
 
  • #9
You are right, it will be difficult to make such a cell. Maybe we should use a melt instead of a solution. But it is interesting to discuss the issue for the sake of theory.
 
  • #10
This is a classical problem in electrochemisty. You can find other tables of standard potentials, E°s, of half cell reactions having the same numerical value but opposite sign, for the reactions in your table . For example for the Li/Li+ -3.040V. Thus, every reaction in your table and that table will have opposite signs for the values of E°s. Therefore, the question arises whether the potential of LI/Li+ is +3.040V or -3.040V? The American tables give the positive value and the British tables give the negative value. Much can be said in support of each. This issue was resolved by an international convention, which uses the negative value for this half cell E°. Without going into too much of a detail, I shall be brief.

The way to understand the relation between E° and the ΔG° and the corresponding spontaneity is this way: Choose a reaction from the table. Combine it with H/H+ reaction. You will get a voltaic cell. A spontaneous reaction, in principle, is possible. Take for example, the Li/Li+ and couple it with SHE. You will get a cell with a E° value of 3.040V. In this cell Li goes to Li+ spontaneously and H+ goes to H2 spontaneously.

Now take, Cu/Cu2+ reaction. Combine it with H/H+ reaction. You will get a voltaic cell. A spontaneous reaction, in principle, is possible. You will get a cell with a E° value of 0.337V. In this cell H2 goes to H+ spontaneously and Cu2+ goes to Cu spontaneously.
Now you can think of combining Li/Li+ and Cu/Cu2+ reactions (or any two reactions for that matter). You get a cell with a E° value of the difference of the two E° values, 3.377V. In this cell Li goes to Li+ spontaneously and Cu2+ goes to Cu spontaneously.

Finally, a positive value of E° for a half cell reaction in a standard table of E° values does not indicate that it is a spontaneous reaction, in as much as a negative value of E° for a half cell reaction in that table of E° values does not indicate a nonspontaneous reaction.

A half cell reaction does not occur by itself. So, when combined with another half cell reaction, a cell is formed and the two half cell reactions occur spontaneously (as you guessed correctly) to give a spontaneous cell reaction with a value of E° for the cell which is the difference between the two E°s of the individual half cells chosen.

P. Radhakrishnamurty
 
  • #11
Thank you very much for a detailed answer and explanation.

Is there an easy way to say which electrode is going to be an anode and which cathode when I randomly choose two half reactions from the table to form a voltaic cell.

Thanks a lot,
CroSinus
 
  • #12
In the table you have chosen, the upper couple that you choose acts as anode (the negative terminal) and the lower couple the cathode (the positive terminal) of the battery.

P. Radhakrishnamurty
 
  • #13
OK, thanks for the answer. What will happen if I take both electrodes from the same side of the table. For example, from the upper part.

CS
 
  • #14
When you take two couples at random (both can be from the same side of zero (not of the table!)) one will be upper and the other lower.
You can go about doing what you want, with that understanding.

P. Radhakrishnamurty
 

1. Can any two electrodes from the table make voltaic cell?

Yes, any two electrodes from the table can be used to make a voltaic cell, as long as they have different reduction potentials. The more positive electrode will serve as the anode, while the more negative electrode will serve as the cathode.

2. How do I know which electrode will serve as the anode and which will serve as the cathode?

The electrode with the more positive reduction potential will serve as the anode, while the electrode with the more negative reduction potential will serve as the cathode.

3. Can I use any type of electrode for a voltaic cell?

No, only certain types of electrodes can be used for a voltaic cell. These include metals, such as copper or zinc, and non-metals, such as carbon or platinum.

4. Can I use electrodes from different elements to make a voltaic cell?

Yes, you can use electrodes from different elements to make a voltaic cell. In fact, using different types of electrodes can create a larger potential difference and produce a stronger electric current.

5. How do I determine the potential difference of a voltaic cell using two different electrodes?

The potential difference of a voltaic cell is determined by the difference in reduction potentials between the two electrodes. You can calculate this by subtracting the reduction potential of the anode from the reduction potential of the cathode.

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