Can anyone check my work? 1st Order ODE Initial Value Problem (Repost)

1. Sep 8, 2008

MustangGt94

Repost with attachment ><

1. The problem statement, all variables and given/known data

dy/dt + ty/(1+t^2) = t/(1+t^2)^1/2 y(1) = 2

Need to solve this initial value problem. The equation is a 1st order ODE

2. Relevant equations

3. The attempt at a solution

I've attached my solution to the problem. Just wondering if anyone can check my work. I solved the problem using the Integrating factor method u(t).

Thank You!
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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2. Sep 8, 2008

Nolgosphere

Your attachment is still pending approval as I write this.

Another approach is to multiply both sides by (1+t^2)^1/2 and observe that the LHS is the derivative, with respect to t, of a product. The integration becomes straight forward.