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Can anyone check my work? 1st Order ODE Initial Value Problem (Repost)

  1. Sep 8, 2008 #1
    Repost with attachment ><

    1. The problem statement, all variables and given/known data

    dy/dt + ty/(1+t^2) = t/(1+t^2)^1/2 y(1) = 2

    Need to solve this initial value problem. The equation is a 1st order ODE

    2. Relevant equations



    3. The attempt at a solution

    I've attached my solution to the problem. Just wondering if anyone can check my work. I solved the problem using the Integrating factor method u(t).

    Thank You!
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Sep 8, 2008 #2
    Your attachment is still pending approval as I write this.

    Another approach is to multiply both sides by (1+t^2)^1/2 and observe that the LHS is the derivative, with respect to t, of a product. The integration becomes straight forward.
     
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