Can anyone help me proofing this? This is not homework.

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SUMMARY

The discussion focuses on deriving Green's function using the chain rule in multivariable calculus. The equation presented is \frac{x}{r} \frac{\partial u}{\partial x} + \frac{y}{r} \frac{\partial u}{\partial y} + \frac{z}{r} \frac{\partial u}{\partial z} = \frac{\partial u}{\partial r}, where r=\sqrt{x^2+y^2+z^2}. The user seeks guidance on applying the chain rule, specifically how to express \frac{\partial x}{\partial r}. The key insight provided is that \frac{\partial r}{\partial x}=\frac{x}{r}, which is crucial for progressing in the proof.

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yungman
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This is part of a bigger derivation of Green's function. The book just jump to the ending and I cannot understand how to do this. I need someone to give me guidence how to proof this:

[tex]\frac{x}{r} \frac{\partial u}{\partial x} + \frac{y}{r} \frac{\partial u}{\partial y} +\frac{z}{r} \frac{\partial u}{\partial z} \;=\; \frac{\partial u}{\partial r}[/tex]

Where

[tex]r=\sqrt{x^2+y^2+z^2}[/tex]

This is not a homework problem.

Thanks
 
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Use the chain rule:

[tex]\frac{\partial u}{\partial r}=\frac{\partial u}{\partial x}\frac{\partial x}{\partial r}+\cdots[/tex]
 
cristo said:
Use the chain rule:

[tex]\frac{\partial u}{\partial r}=\frac{\partial u}{\partial x}\frac{\partial x}{\partial r}+\cdots[/tex]

I thought of that, but what is [tex]\frac{\partial x}{\partial r}[/tex]

I know

[tex]\frac{\partial r}{\partial x}=\frac{x}{r}[/tex]

That's exactly where I got stuck!
 

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