The discussion centers on simplifying the Boolean expression ab'c + a'b + bc' + abc to B + AC using Karnaugh maps (K-map) and Boolean algebra. Participants confirm that K-maps can effectively reduce the expression, while also emphasizing that algebraic methods, such as De Morgan's theorem, can achieve the same results. The consensus is that while K-maps offer a straightforward approach, algebraic simplification is always possible, albeit potentially more complex.
PREREQUISITESStudents, engineers, and computer scientists interested in digital logic design, Boolean algebra simplification, and optimization of logic circuits.
Do you know about karnaugh maps? The reduction to B + AC is trivial and obvious if you do.kukumaluboy said:ab'c + a'b + bc' + abc
= ac + a'b + bc' (How to further reduce this?)
Kmap gives B + AC
You can reduce ac + a'b + bc' further using DeMorgan's theorem as a first step.kukumaluboy said:As in is there a boolean algebra way?
Sorry, yes, your subject line does say algebraic simplification. As milesyoung said, use deMorgan's theorems.kukumaluboy said:As in is there a boolean algebra way? Yea i know it can be done in kmap. Just curious
First question: do you know De Morgan's theorems?kukumaluboy said:As in is there a boolean algebra way? Yea i know it can be done in kmap. Just curious