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## Homework Statement

Simplify the following Boolean expressions to a minimum number of literals

(a+b+c')(a'b'+c)

**2. The attempt at a solution**

Whenever I tried this I made no progress in reducing the number of literals, I just reordered the expression.

(a+b+c')(a'b'+c)

=aa'b'+a'bb'+a'b'c'+ac+bc+cc'

=0b'+a'0+a'b'c'+ac+bc+0

=0+0+a'+b'+c'+ac+bc+0

=a'b'c'+ac+bc

=a'b'c'+c(a+b)

I began with 6 literals and ended with 6. What else can I try?