Simplifying Boolean Algebra: How to Simplify Complex Boolean Expressions

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Discussion Overview

The discussion centers on simplifying complex Boolean expressions, specifically focusing on the expression (A OR C) AND NOT(C AND A AND B OR C AND A AND NOT B) and its equivalent forms. Participants explore various rules of Boolean algebra and their applications in simplification attempts.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about how to expand (CAB + CAB')' for simplification, noting that their attempts lead to incorrect results.
  • Another participant suggests that relevant equations are necessary for simplification and encourages listing them to identify which are needed.
  • There is confusion regarding the application of the rule (A+B)' = A'B' in the context of (CAB + CAB').
  • One participant questions the validity of a proposed simplification, stating it leads to a false result unless the NOT operation is considered correctly.
  • A participant emphasizes the importance of taking one step at a time in the simplification process.
  • There is a correction regarding the misunderstanding that (XY)' equals X'Y', clarifying that this is not the case.
  • Another participant attempts to show that (CAB + CAB') can be simplified to CA(B+B'), but acknowledges that the NOT portion is crucial and was initially overlooked.
  • A later reply indicates that the simplification process is easier when the NOT operation is applied correctly, suggesting a need for careful consideration in each step.

Areas of Agreement / Disagreement

Participants express various viewpoints and uncertainties regarding the simplification process, with no clear consensus reached on the correct approach or final expression. Disagreements exist about the application of specific Boolean rules and the steps taken in simplification.

Contextual Notes

Some participants note missing assumptions and the importance of correctly applying Boolean algebra rules, indicating that the discussion may depend on precise definitions and interpretations of the rules involved.

Jaehyun
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Homework Statement
(A OR C) AND NOT(C AND A AND B OR C AND A AND NOT B)
or
(A + C) (CAB + CAB')'

Relevant Equations
(A+B)' = A'B'
A(B+C) = (AB) + (AC)
(AB)' = A' + B'

The attempt at a solution
I'm not sure how I'm suppose to expand (CAB + CAB')' for simplifying. I keep arriving at false which shouldn't be the case.

(A + C) (CA)' (B + B')' (I'm not sure if this is what your suppose to do)

or

(A + C) (C'A'B'C'A'B) (Not sure if i used (A+B)' = A'B' correctly)

Thanks - Jay
 
Last edited:
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Hello Jaehyun, :welcome:

Pity you deleted part of the template: relevant equations are needed to do what you want. List a few and you'll see which you need
 
BvU said:
Hello Jaehyun, :welcome:

Pity you deleted part of the template: relevant equations are needed to do what you want. List a few and you'll see which you need

I'm confused on how this rule: (A+B)' = A'B' is used to help with (CAB + CAB')'.
 
I was searching for (xyp + xyq) = xy (p+q)
 
BvU said:
I was searching for (xyp + xyq) = xy (p+q)

I don't think this rule would work as it leads to a false (CA)' (B + B')' = (CA)' (1)' = 0 unless this does not work for NOT.
 
No. Do one step at a time.
 
By the way, (XY)' ≠ X'Y' !
 
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(A + C) (CAB + CAB')'
(A + C) (CA)' (B + B')'
(A + C) (C' + A') (B + B')'
(AC' + AA' + CC' + CA') (B + B')'
(AC' + CA') (B + B')'

So then (B + B')' = 0 meaning there is no simplified expression?
 
Last edited:
Jaehyun said:
I'm confused on how this rule: (A+B)' = A'B' is used to help with (CAB + CAB')'.
My "I was searching for (xyp + xyq) = xy (p+q)" : was meant to lure you into (CAB + CAB') = CA(B+B') = CA

(A + C) (CAB + CAB')' does NOT lead to (A + C) (CA)' (B + B')' !
 
  • #10
BvU said:
My "I was searching for (xyp + xyq) = xy (p+q)" : was meant to lure you into (CAB + CAB') = CA(B+B') = CA

(A + C) (CAB + CAB')' does NOT lead to (A + C) (CA)' (B + B')' !

But (CAB + CAB') = CA(B+B') = CA is missing the NOT portion (CAB + CAB')'.

Edit: I was rushing the question so much and I finally realized what I was doing wrong thanks BvU for putting up with me it's 2am where I live and I'm clearly not in the right mind at the moment. Solved.
 
Last edited:
  • #11
Yes. The NOT portion comes afterwards. (CA)' is easier to do than what you had before.

Great. Advice: go a bit slower :smile: The speed will come with experience; in the beginning taking small steps and doing it right are more important.
 

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