Can Borel resummation be applied to integrals ?

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SUMMARY

The discussion centers on the application of Borel resummation to integrals, specifically examining the integral of a function f(x) from 0 to infinity. The integral is expressed as a Laplace transform involving the Gamma function, represented as G(x+1+u). The conclusion drawn is that the Laplace transform evaluated at s=1 yields the Borel sum of the integral of f(x), thereby establishing a direct relationship between Borel resummation and the Gamma function in this context.

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This discussion is beneficial for mathematicians, physicists, and researchers interested in advanced calculus, particularly those exploring the intersections of Borel resummation, Laplace transforms, and the Gamma function.

Klaus_Hoffmann
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The question is can we obtain the 'Borel sum' of an integral of f(x) from 0 to infinity as the Laplace transform of

[tex]\int_{0}^{\infty}dx \frac{f(x)}{\Gamma(x+1+u)t^{x+u}[/tex]

where 'alpha' is a real or Complex number
 
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i meant (but the nasty latex does not work)

[tex]\int_{0}^{\infty} dx \frac{f(x)}{G(x+1+u)}t^{x+u}[/tex]

then the Laplace transform evaluated at s=1 is the 'Borel sum' of the integral

[tex]\int_{0}^{\infty} dx f(x)[/tex]

Of course G(x) is the 'Gamma function' generalization of factorial n!
 
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