lokofer
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Borel "resummation"...
Let be a divergent series:
[tex]\sum _{n=0}^{\infty} a(n)[/tex] (1)
then if you "had" that [tex]f(x)= \sum _{n=0}^{\infty} \frac{a(n)}{n!}x^{n}[/tex]
You could obtain the "sum" of the series (1) as [tex]S= \int_{0}^{\infty}dte^{-t}f(t)[/tex] in case the integral converges...
- Yes that's "beatiful" the problem is ..what happens if the coefficients a(n) are complicate?..then how can you obtain the sum of the series?...
- By the way i think that Borel resummation can be applied if [tex]f(t)=O(e^{Mt})[/tex] M>0, but what happens if f(t) grows faster than any positive exponential?..
Let be a divergent series:
[tex]\sum _{n=0}^{\infty} a(n)[/tex] (1)
then if you "had" that [tex]f(x)= \sum _{n=0}^{\infty} \frac{a(n)}{n!}x^{n}[/tex]
You could obtain the "sum" of the series (1) as [tex]S= \int_{0}^{\infty}dte^{-t}f(t)[/tex] in case the integral converges...
- Yes that's "beatiful" the problem is ..what happens if the coefficients a(n) are complicate?..then how can you obtain the sum of the series?...
- By the way i think that Borel resummation can be applied if [tex]f(t)=O(e^{Mt})[/tex] M>0, but what happens if f(t) grows faster than any positive exponential?..
