Can Every Number Be Expressed as a Sum of 1's and 2's in Fibonacci Ways?

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SUMMARY

Every natural number \( n \) can be expressed as a sum of 1's and 2's in \( F_{n+1} \) distinct ways, where \( F_{n+1} \) represents the \( n+1 \)-th Fibonacci number. The proof involves demonstrating the base case for \( n = 1 \) and establishing a recursive relationship for \( n = p \) and \( n = p + 1 \). The relationship is defined as \( P(n+1) = P(n) + P(n-1) \), which mirrors the Fibonacci sequence. This confirms that the number of summation sequences corresponds directly to Fibonacci numbers.

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Homework Statement



Show that [itex]\forall n \in \mathbb{N}[/itex], the number n can written as a sum of 1's and 2's in [itex]F_{n+1}[/itex] number of ways. [itex]F_{n+1}[/itex] is the n+1:th number in the Fibonacci numbers. The order of summation makes a difference only when you get different sequences eg. 3 = 1 + 1 + 1 = 2 + 1 = 1 + 2.

The Attempt at a Solution



(1) Show that it is true for n = 1:

The number one can be written as precisely one sum of the numbers 1 and 2:

1

This is also the second of the Fibonacci numbers.

(2) Show that if it is true for n = p, it is true for n = p + 1:

Assume that p can be written [itex]F_{n+1}[/itex] different ways as the sum of 1's and 2's.

It is clear that p + 1 can be written in at least as many ways, since you can just add a 1 to the different ways you can write p. However, I seem to be having some trouble with how many additional ways that it can be written. I imagine that since adding a 1 to the each of the earlier ways enables you to form additional ways by merging the added 1 to another 1 in the different sums where they happen to exist. However, for even numbers, there will be at least one way that includes only 2's, in which case this would not work.
 
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Let P(n) be the number of ways to write n as the sum of a sequence of 1's and 2's. To get P(n+1) you can either append a 1 to a sequence that sums to n (a total of P(n) ways), or you can append a 2 to a sequence that sums to n-1 (a total of P(n-1) ways). Does that recursion remind you of Fibonacci?
 

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