- #1
Nick Jackson
- 13
- 0
Hello,
well here's my problem: I got this integral and I don't know how to calculate it (I am trying to find if there exists a k that satisfies this relation) :
[tex] \int_0^k \frac{1}{ ( 4k-4r-2 ) ! ( 4r+1 ) ! }\, \left ( \frac{y}{x} \right )^{4r} dk = \int_0^k \frac{1}{ ( 4k-4r ) ! ( 4r+3 ) ! }\, \left ( \frac{y}{x} \right )^{4r} dk [/tex]
The problem is mainly in the factorial part (they are results of binomial coefficients as you may see)
Any help?
P.S. There probably doesn't exist such a k.
well here's my problem: I got this integral and I don't know how to calculate it (I am trying to find if there exists a k that satisfies this relation) :
[tex] \int_0^k \frac{1}{ ( 4k-4r-2 ) ! ( 4r+1 ) ! }\, \left ( \frac{y}{x} \right )^{4r} dk = \int_0^k \frac{1}{ ( 4k-4r ) ! ( 4r+3 ) ! }\, \left ( \frac{y}{x} \right )^{4r} dk [/tex]
The problem is mainly in the factorial part (they are results of binomial coefficients as you may see)
Any help?
P.S. There probably doesn't exist such a k.