Can g(w) Satisfy This ODE in Fourier Analysis?

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SUMMARY

The discussion centers on the relationship between the function g(w), defined as the Fourier transform of exp(if(x)), and its satisfaction of the ordinary differential equation (ODE) -if'(x)∂g(w)/∂w + wg(w) = 0. The integral presented, ∫_{-∞}^{∞}dx e^{if(x)+iwx} = g(w), serves as the foundation for this inquiry. The participants emphasize the necessity of proving that g(w) adheres to the specified ODE under the condition that exp(if(∞)) = 0.

PREREQUISITES
  • Understanding of Fourier transforms, specifically g(w) = ∫_{-∞}^{∞}dx e^{if(x)+iwx}
  • Knowledge of ordinary differential equations (ODEs) and their applications
  • Familiarity with complex functions and their properties
  • Basic principles of limits, particularly involving infinity in mathematical expressions
NEXT STEPS
  • Study the properties of Fourier transforms and their implications in solving ODEs
  • Explore the derivation techniques for proving ODEs involving complex functions
  • Investigate the conditions under which Fourier transforms converge, particularly at infinity
  • Learn about the implications of boundary conditions in differential equations
USEFUL FOR

Mathematicians, physicists, and students engaged in advanced calculus or differential equations, particularly those interested in Fourier analysis and its applications in solving ODEs.

tpm
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it's a curiosity more than a HOmework, given the integral:

[tex]\int_{-\infty}^{\infty}dx e^{if(x)+iwx}=g(w)[/tex]

Where g(w) can be viewed as the Fourier transform of exp(if(x)) then my question is if we can prove g(w) satisfies the ODE:

[tex]-if'(x)\frac{\partial g(w)}{\partial w}+wg(w)=0[/tex]

for simplicity we can impose [tex]exp(if(\infty))=0[/tex] and the same for

-oo
 
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Why don't you derive and show us if it's true?
 

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