kanato
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Demystifier said:If the wave function has definite quantum numbers n,l,m then the trajectory is a circle with the angular velocity proportional to m. In particular, when m=0 (which is the case when n=0) then the particle is at rest.
Uh.. how does that work? If the electron in a 1s state is at rest, then why does it have a nonzero expectation value for its kinetic energy? (By the virial theorem, the electron should have a kinetic energy expectation value of <p^2/2m> = +13.6 eV.) I can understand that the particle could be at rest but have uncertainty in position, but I don't understand how the particle can be at rest and have kinetic energy at the same time.