Can Recurrence Relations with Complex Inequalities Be Simplified?

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The discussion focuses on simplifying the recurrence relation defined by the inequality \(\Psi(m,n) \leq \Psi\left(\left \lfloor\frac{m}{2}\right\rfloor,n_1\right) + \Psi\left(\left \lceil\frac{m}{2}\right\rceil,n_2\right) + 16n^* + 11m \lceil\text{log }m\rceil\). The proposed approach involves setting \(m = 2k\) to simplify the recursion. However, the complexity introduced by the arbitrary partition of \(n\) raises questions about the feasibility of deriving a complete analytical solution beyond computational methods.

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seeker101
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Any suggestions on how to approach solving:

\Psi(m,n) \leq \Psi\left(\left \lfloor\frac{m}{2}\right\rfloor,n_1\right) + \Psi\left(\left \lceil\frac{m}{2}\right\rceil,n_2\right) + 16n^*+11m \lceil\text{log }m\rceil<br />

where n = n_1 + n_2 + n^*
 
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I would start by making m = 2k. This would give you a more simple recursion, but that inequality and the arbitrary partition of n makes me wonder if it's possible to go beyond a partial computational solution.
 

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