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The problem is:
For the baseball diamond in exercise 33, suppose the player is running from first to second at a speed of 28 feet per second. Find the rate at which the distance from home plate is changing when the player is 30 feet from second base.
(the picture basically shows a square with 90 ft sides)
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My solution
Given: dy/dt = 28 ft/sec
Find: ds/dt when x=30
902y2=s2
0 +2y(dy/dt)=2s(ds/dt)
2(60)(28)=2(30√13)(ds/dt)
56/(√13) ft/sec=ds/dt
__________________________
I'm not really sure if its the correct answer because I always seem to mix up negative signs and I wasnt sure if this required one.
If you really need to see the picture its found here:
http://books.google.com/books?id=E5...he player is 30 feet from second base&f=false
Page 151 #34
For the baseball diamond in exercise 33, suppose the player is running from first to second at a speed of 28 feet per second. Find the rate at which the distance from home plate is changing when the player is 30 feet from second base.
(the picture basically shows a square with 90 ft sides)
__________________________________________________
My solution
Given: dy/dt = 28 ft/sec
Find: ds/dt when x=30
902y2=s2
0 +2y(dy/dt)=2s(ds/dt)
2(60)(28)=2(30√13)(ds/dt)
56/(√13) ft/sec=ds/dt
__________________________
I'm not really sure if its the correct answer because I always seem to mix up negative signs and I wasnt sure if this required one.
If you really need to see the picture its found here:
http://books.google.com/books?id=E5...he player is 30 feet from second base&f=false
Page 151 #34