Can someone check my answers (Closed and open tubes)

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Homework Help Overview

The discussion revolves around the fundamental frequencies of tubes with different end conditions, specifically a tube open at both ends and a tube open at one end. The original poster presents a problem involving the calculation of the fundamental frequency of an original tube based on the frequencies of its segments. Additionally, there is a question regarding the refraction of sound in relation to temperature changes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate the fundamental frequencies of the two segments to the length of the original tube, using equations for open and closed tubes. Some participants question the validity of the calculations and the reasoning behind the assumptions made regarding the lengths and frequencies.

Discussion Status

The discussion appears to be ongoing, with some participants expressing uncertainty about the original poster's calculations. There is a request for feedback on the work presented, indicating a desire for clarification rather than a resolution. The image related to the refraction question has been shared again, suggesting that visual context is important for the discussion.

Contextual Notes

The original poster's approach involves specific equations for tube frequencies, and there may be constraints related to the interpretation of the refraction question. The lack of consensus on the calculations suggests that further exploration of the assumptions and methods is needed.

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Homework Statement


A tube, open only at one end, is cut into two shorter (non-equal)
lengths. The piece open at both ends has a fundamental frequency
of 425 Hz, while the piece open only at one end has a fundamental
frequency of 675 Hz. What is the fundamental frequency of the
original tube ?

also
Which of the following describes the relative temperatures in the refraction of sound. N is the normal line.

http://img511.imageshack.us/my.php?image=refractionfe5.jpg

Homework Equations


L1+L2=L
V/2L=frequency of open tube
V/4L=Frequency of closed tube

The Attempt at a Solution


For the first question I said the V/2(L1)=425 and V/4(L2)=675. so V=850L1 and V=2700L2. so I solved for L1 and got L1=3.176L2 and using the above equation L=4.176L2. So 2700L2/4(4.176L2)=161.63Hz, it seems resonable but I just want to see if I am right.

As for the other question I said that it moves from cold air to warm air since the angle gets larger and then from warm air to cold air since the angle gets smaller.
 
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Couldn't see the image, but I think this work is good.
 
Here is the image again

http://img511.imageshack.us/img511/4403/refractionfe5.jpg
 
Last edited by a moderator:
Anyone?
 

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