- #1
omega16
- 20
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Find the prime factorization of 6 in Q[sqrt(-1)].
Ans : Since 6 = 2*3
so 6 = (1+sqrt(-1)) (1-sqrt(-1)) *3 Q.E.D.
Do I need to add anything to it? Am I done with this question? Please kindly advise me. Thank you very much.
Ans : Since 6 = 2*3
so 6 = (1+sqrt(-1)) (1-sqrt(-1)) *3 Q.E.D.
Do I need to add anything to it? Am I done with this question? Please kindly advise me. Thank you very much.