Can someone check this for me?

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Homework Help Overview

The discussion revolves around finding the prime factorization of the number 6 in the field Q[sqrt(-1)]. The original poster presents a factorization and seeks confirmation on the completeness of their response.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the primality of the factors presented, specifically regarding the elements 1+sqrt(-1), 1-sqrt(-1), and 3 in the context of the field Q(sqrt(-1)).

Discussion Status

The discussion is ongoing, with participants exploring the nature of the factors and their primality within the specified field. There is no explicit consensus yet on the validity of the original poster's factorization.

Contextual Notes

There appears to be a focus on the definitions of prime elements in the context of the field Q(sqrt(-1)), which may not be fully addressed in the original post.

omega16
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Find the prime factorization of 6 in Q[sqrt(-1)].

Ans : Since 6 = 2*3
so 6 = (1+sqrt(-1)) (1-sqrt(-1)) *3 Q.E.D.

Do I need to add anything to it? Am I done with this question? Please kindly advise me. Thank you very much.
 
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How do you know those are prime?
 
because 2 and 3 are prime.
 
I mean 1+sqrt(-1), 1-sqrt(-1), and 3 in the field Q(sqrt(-1)).
 

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