Can someone help me to calculate the velocity at Stack Tip?

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Homework Help Overview

The discussion revolves around calculating the velocity at the stack tip in a fluid dynamics context, specifically concerning a system involving compressible gases and varying diameters. The original poster questions the applicability of the continuity equation due to the distance involved and the nature of the fluid.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the use of the continuity equation (V1A1 = V2A2) and express concerns about its applicability to compressible fluids. There is also confusion regarding the units of velocity and flow rate presented in the problem.

Discussion Status

Some participants have provided insights into the nature of the fluid and the relevance of the equation, while others have pointed out potential misunderstandings in the problem's presentation. The discussion is ongoing, with various interpretations being explored.

Contextual Notes

There is mention of a distance of 2.5 m and the potential effects on calculations, as well as confusion regarding the units used for velocity and flow rate. Participants are considering the implications of these factors on the problem at hand.

Suradanai
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Homework Statement


How can we calculate the velocity at stack tip if the distance of larger diameter is 2.5 m?
I think i cannot use the equation of V1A1 = V2A2 because they may have some effect from 2.5 m of distance.
Thank you very much.

Homework Equations


Q1=Q2

The Attempt at a Solution


V1A1 = V2A2
45.74*2.4 = V2*6.16
V2 = 17.82 m/s
 

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Suradanai said:

Homework Statement


How can we calculate the velocity at stack tip if the distance of larger diameter is 2.5 m?
I think i cannot use the equation of V1A1 = V2A2 because they may have some effect from 2.5 m of distance.
I think you're right. That formula applies to incompressible fluids like water. The flue gases are of course compressible.

I'm afraid I must leave this one to other helpers.
 
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There seems to be some confusion in the diagram. It shows a "velocity" in m3/s, asks about another such in the same units, but also quotes a "flow rate" in those units at the "exhaust temperature". How does that relate to the two velocities?
I have a suspicion the two "velocities" are supposed to be m/s. Given the diameter, that would seem to be consistent with the volumetric flow rate. If so, it makes the question much easier; you can ignore most of the information.
 
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rude man said:
I think you're right. That formula applies to incompressible fluids like water. The flue gases are of course compressible.

I'm afraid I must leave this one to other helpers.
Thank you very much, now I am looking the gas equation also that can apply this issue.
 
haruspex said:
There seems to be some confusion in the diagram. It shows a "velocity" in m3/s, asks about another such in the same units, but also quotes a "flow rate" in those units at the "exhaust temperature". How does that relate to the two velocities?
I have a suspicion the two "velocities" are supposed to be m/s. Given the diameter, that would seem to be consistent with the volumetric flow rate. If so, it makes the question much easier; you can ignore most of the information.
Oh!, that's my mistake, the right should be (m/s) as you said.
Thank you very much
 
Suradanai said:
Oh!, that's my mistake, the right should be (m/s) as you said.
Thank you very much
"The right"? Do you mean the "flow rate"? I would have thought that was m3/s, and the two "velocities" should be m/s.
 

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