Can the Peng-Robinson EOS be solved explicitly for T?

  • Thread starter Thread starter cjc0117
  • Start date Start date
Click For Summary
SUMMARY

The Peng-Robinson Equation of State (EOS) can be solved explicitly for temperature (T) by substituting T with t2, allowing for the extraction from the square root. The equation is defined as P = (RT)/(v-b) - [a(1+k(1-√(T/Tc)))²]/[v(v+b)+b(v-b)]. The solution involves manipulating the equation into a quadratic form, which can then be solved for t. This method was confirmed by user gneill during the discussion.

PREREQUISITES
  • Understanding of the Peng-Robinson Equation of State
  • Familiarity with algebraic manipulation of equations
  • Knowledge of thermodynamic properties (pressure, volume, temperature)
  • Basic skills in quadratic equation solving
NEXT STEPS
  • Study the derivation and applications of the Peng-Robinson EOS
  • Learn about other equations of state, such as the Redlich-Kwong EOS
  • Explore numerical methods for solving nonlinear equations
  • Investigate the impact of critical properties on phase behavior
USEFUL FOR

Engineers, thermodynamicists, and students involved in chemical engineering or physical chemistry who are working with equations of state and phase equilibria.

cjc0117
Messages
91
Reaction score
1
I'm not sure if this is the right forum to ask this question, but it arose as part of an engineering problem, so here goes.

The Peng-Robinson EOS is as follows:

P=\frac{RT}{v-b}-\frac{a[1+k(1-\sqrt{\frac{T}{T_{c}}}]^{2}}{v(v+b)+b(v-b)}

I'm just wondering if this equation can be solved explicity for T. I tried but I had no luck.
 
Physics news on Phys.org
Presumably T is a positive value. Replace T with t2. That'll let you pull it out of the square root. Solve the resulting quadratic for t...
 
Okay, I figured it out. Thank you gneill!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
3K
Replies
0
Views
2K
Replies
3
Views
7K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
3
Views
2K
Replies
30
Views
4K
  • · Replies 23 ·
Replies
23
Views
3K