- #1
Georgepowell
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- 0
I am not too good at maths, but I have noticed a few patterns in some basic functions.
For example, when comparing a function to the inverse of that function, the inverse of the function can often come out with multiple values, but the original one always leads to one definite number. For example, the 'square' and 'square-root' function. The square root is usually "plus or minus" the square root, and hence the two possible values. The same with trigonometric functions.
Another pattern I noticed when comparing the inverse function to the original one is that it doesn't matter about the order of the computation of the normal function, but then when calculating the inverse, the order matters. e.g.
7*23*4*5 is the same as 7*(23*(4*5)), but 7/(23/(4/5)) is not the same as (7/23)/(4/5).
Another point: every function has a 'base', for example the multiplication function can be written as f[y](x)= x*y (where [y] is the 'base'). The inverse of SOME functions can be found simple by changing the base of the original function to [1/y]:
f[1/y](x) = x*(1/y) = x/y
But other functions do not work in the same way. For example with logarithms:
log[a](x)= y
but,
log[1/a](y) does not = x
Does this mean that all the different functions can be sorted into different groups? Sorted into groups that share properties.
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And now onto the physics:
Could someone calculate a function that simulates the passing of time? In which the necessary values of the universe (perhaps the velocities and positions of particles?) are changed to give the values of the particles a second later? Obviously to develop a single function to do this would be mind boggling, so this is only a theoretical question.
What would this function act like? Would the inverse of this function lead to even more possible values that the forward version? (seeing as quantum mechanics adds an inherent randomness, and hence multiple values). And could it possibly lead to less values than the forward version?
I welcome any help or information on this ponder of mine, including criticisms. As I said, I'm not an experienced mathematician so I might have got something wrong.
For example, when comparing a function to the inverse of that function, the inverse of the function can often come out with multiple values, but the original one always leads to one definite number. For example, the 'square' and 'square-root' function. The square root is usually "plus or minus" the square root, and hence the two possible values. The same with trigonometric functions.
Another pattern I noticed when comparing the inverse function to the original one is that it doesn't matter about the order of the computation of the normal function, but then when calculating the inverse, the order matters. e.g.
7*23*4*5 is the same as 7*(23*(4*5)), but 7/(23/(4/5)) is not the same as (7/23)/(4/5).
Another point: every function has a 'base', for example the multiplication function can be written as f[y](x)= x*y (where [y] is the 'base'). The inverse of SOME functions can be found simple by changing the base of the original function to [1/y]:
f[1/y](x) = x*(1/y) = x/y
But other functions do not work in the same way. For example with logarithms:
log[a](x)= y
but,
log[1/a](y) does not = x
Does this mean that all the different functions can be sorted into different groups? Sorted into groups that share properties.
------
And now onto the physics:
Could someone calculate a function that simulates the passing of time? In which the necessary values of the universe (perhaps the velocities and positions of particles?) are changed to give the values of the particles a second later? Obviously to develop a single function to do this would be mind boggling, so this is only a theoretical question.
What would this function act like? Would the inverse of this function lead to even more possible values that the forward version? (seeing as quantum mechanics adds an inherent randomness, and hence multiple values). And could it possibly lead to less values than the forward version?
I welcome any help or information on this ponder of mine, including criticisms. As I said, I'm not an experienced mathematician so I might have got something wrong.