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Proof of KE loss in inelastic collision

  1. Oct 20, 2015 #1
    1. The problem statement, all variables and given/known data
    Prove that a perfectly inelastic collision loses more kinetic energy than a partially inelastic collision. Given: $$m_1, m_2, v_{1i}, v_{2i}, v_{1f}, v_{2f}$$

    2. Relevant equations
    $$KE = \frac{1}{2}mv^2$$

    3. The attempt at a solution
    From conservation of momentum:
    $$P_{inelastic} : m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_f$$
    $$P_{partial} : m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$$

    I'm not sure how to progress from this. Thanks.
  2. jcsd
  3. Oct 20, 2015 #2

    Simon Bridge

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    Compare energy before collision with energy after collision for each case.
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