Can two charged particles both be 40 nC if the field is zero between them?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
16 replies · 2K views
-EquinoX-
Messages
561
Reaction score
1

Homework Statement


if I have two charged particles A and B and are distanced 8 cm apart. At a point 4 cm from
A, the net electric field is 0. The charge of A is 40 nC. What can we conclude about the charge of B?


Homework Equations





The Attempt at a Solution



From my point of view B can be 40nC as well.. however I am not sure if there are some other answers as well. I am pretty sure there can be more than 1 answer
 
Physics news on Phys.org
There are two points that are 4cm from A where the fields can cancel. They can cancel at the midpoint of A and B or they can cancel 4cm away from A on the opposite side of A from B.
 
hmm..not clear on what you meant here.. do you mind giving me a picture? how about B's charged magnitude? how large does it have to be?
 
I'm not very good at pictures. Suppose the charges are on the x-axis. Put A at x=0cm and B at x=8cm. Then the third location could be either at x=4cm or x=(-4)cm. If x=4cm, I agree with you, the charges should be equal. How about at x=(-4)cm?
 
well if it's at -4cm then the distance between A and B is only 4 cm away right? A is at 0 and B is at -4?
 
No, A stays at 0cm and B stays at 8cm. Call the third point C=(-4)cm. C is 4cm from A and 12cm from B, right? What does the charge at B have to be to cancel the E field at C?
 
I get the picture you're trying to say now. However...how do I calculate the magnitude of B based on that info??
 
Use E=k*Q/r^2. You know the distance r for each charge and you know Q for A is 40nC. Write an equation that they sum to zero and solve for the charge at B.
 
so EA + EB = 0
k*40/4^2 + k*X/12^2 = 0

and I need to solve for X?
 
Yeah, sure. Solve for x!
 
okay the answer I got is 360nC, is that right? and are those the only two points from A where the fields cancels?
 
I get -360nC, don't you? The sign is important. At any other point besides those two there is an angle between the two E fields. Can two fields cancel if they are are at different angles?
 
yes, I missed the negative signs.. as far as I know they can't cancel if it's at a different angles.. correct?
 
Yes. Two vectors can only cancel if they are negatives of each other. So they have to point along the same line.
 
okay.. so the conclusion is only these two, where B is 40nC and B is -360nC
 
Seems so to me. Ok with you?
 
Seems fine with me, I am just worried that I missed some answers.