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## Homework Statement

Two particles with a similar charge are held at a distance of 3.2*10^-3 m and then released. The acceleration of the first particle is measured at 7.0 m/s^2, and for the second at 9.0 m?s^2. The mass of the first particle is 6.3*10^-7. What is the mass of the second particle?

## Homework Equations

F=ma F=G*m1*m2/r^2

## The Attempt at a Solution

F1=m1a1 F2=m2a2 (where F1 and F2 are the forces exerted by each particle respectively)

F1 - F2 = G*m1*m2/r^2

(since the particles are similarly charged, they would have forces pointing in opposite directions)

after substitution and making m2 the subject of the formula:

m2 = (m1*a1*r^2)/(Gm1 + a2r^2)

which gives: m2 = 4.31*10^-7

I am not so sure if the method I used is completely correct, can someone please tell me?