Can two different infinite series converge to the same limit?

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SUMMARY

Two different infinite series, \(\sum_{n=1}^{\infty}a_n\) and \(\sum_{n=1}^{\infty}b_n\), both convergent with \(a_n \leq b_n\) for all \(n\) and \(a_n < b_n\) for at least one \(n\), cannot converge to the same limit. The analysis shows that if \(a_n < b_n\) for any \(n\), the partial sums of \(a_n\) will always be less than those of \(b_n\), leading to the conclusion that \(\sum_{n=1}^{\infty}a_n\) is strictly smaller than \(\sum_{n=1}^{\infty}b_n\). This holds true even if \(a_n < b_n\) for infinitely many \(n\).

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raphile
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Hi,

The title of the thread doesn't adequately describe the question I want to ask, so here it is:

Suppose we have two infinite series, \sum_{n=1}^{\infty}a_n and \sum_{n=1}^{\infty}b_n, both of which are convergent. Also suppose a_n \leq b_n for all n, and a_n &lt; b_n for at least one n. Is it possible that they both converge to the same limit? Or can we say that \sum_{n=1}^{\infty}a_n is strictly smaller than \sum_{n=1}^{\infty}b_n?

If the answer to the above question is that they can have the same limit, then what if a_n&lt;b_n for infinitely many n?

Thanks!
 
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Suppose a_i &lt; b_i and that a_n \leq b_n for all n \neq i. Then if \sum_{n \in \mathbb{N}}a_n and \sum_{n \in \mathbb{N}}b_n converge, it is easy to show the following:
\sum_{n \leq i}a_n &lt; \sum_{n \leq i}b_n
\sum_{n &gt; i}a_n \leq \sum_{n &gt; i}b_n
Adding these together gives
\sum_{n \in \mathbb{N}}a_n = \sum_{n \leq i}a_n + \sum_{n &gt; i}a_n &lt; \sum_{n \leq i}b_n + \sum_{n &gt; i}b_n = \sum_{n \in \mathbb{N}}b_n
This should answer your question.
 
There is no way they can have the same limit. If you compare finite sums including at least one n where an < bn, then the a partial sum will be smaller and there is no way it can make up the difference without a term with a > b.
 
Ok, that's great, thanks!
 
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